Optimal. Leaf size=178 \[ \frac {1}{16 (a+b) (1-\csc (x))^2}+\frac {5 a+7 b}{16 (a+b)^2 (1-\csc (x))}+\frac {1}{16 (a-b) (1+\csc (x))^2}+\frac {5 a-7 b}{16 (a-b)^2 (1+\csc (x))}-\frac {\left (8 a^2+21 a b+15 b^2\right ) \log (1-\csc (x))}{16 (a+b)^3}-\frac {\left (8 a^2-21 a b+15 b^2\right ) \log (1+\csc (x))}{16 (a-b)^3}+\frac {b^6 \log (a+b \csc (x))}{a \left (a^2-b^2\right )^3}-\frac {\log (\sin (x))}{a} \]
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Rubi [A]
time = 0.21, antiderivative size = 178, normalized size of antiderivative = 1.00, number of steps
used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3970, 908}
\begin {gather*} -\frac {\left (8 a^2+21 a b+15 b^2\right ) \log (1-\csc (x))}{16 (a+b)^3}-\frac {\left (8 a^2-21 a b+15 b^2\right ) \log (\csc (x)+1)}{16 (a-b)^3}+\frac {b^6 \log (a+b \csc (x))}{a \left (a^2-b^2\right )^3}+\frac {5 a+7 b}{16 (a+b)^2 (1-\csc (x))}+\frac {5 a-7 b}{16 (a-b)^2 (\csc (x)+1)}+\frac {1}{16 (a+b) (1-\csc (x))^2}+\frac {1}{16 (a-b) (\csc (x)+1)^2}-\frac {\log (\sin (x))}{a} \end {gather*}
Antiderivative was successfully verified.
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Rule 908
Rule 3970
Rubi steps
\begin {align*} \int \frac {\tan ^5(x)}{a+b \csc (x)} \, dx &=b^6 \text {Subst}\left (\int \frac {1}{x (a+x) \left (b^2-x^2\right )^3} \, dx,x,b \csc (x)\right )\\ &=b^6 \text {Subst}\left (\int \left (\frac {1}{8 b^4 (a+b) (b-x)^3}+\frac {5 a+7 b}{16 b^5 (a+b)^2 (b-x)^2}+\frac {8 a^2+21 a b+15 b^2}{16 b^6 (a+b)^3 (b-x)}+\frac {1}{a b^6 x}+\frac {1}{a (a-b)^3 (a+b)^3 (a+x)}+\frac {1}{8 b^4 (-a+b) (b+x)^3}+\frac {-5 a+7 b}{16 (a-b)^2 b^5 (b+x)^2}+\frac {8 a^2-21 a b+15 b^2}{16 b^6 (-a+b)^3 (b+x)}\right ) \, dx,x,b \csc (x)\right )\\ &=\frac {1}{16 (a+b) (1-\csc (x))^2}+\frac {5 a+7 b}{16 (a+b)^2 (1-\csc (x))}+\frac {1}{16 (a-b) (1+\csc (x))^2}+\frac {5 a-7 b}{16 (a-b)^2 (1+\csc (x))}-\frac {\left (8 a^2+21 a b+15 b^2\right ) \log (1-\csc (x))}{16 (a+b)^3}-\frac {\left (8 a^2-21 a b+15 b^2\right ) \log (1+\csc (x))}{16 (a-b)^3}+\frac {b^6 \log (a+b \csc (x))}{a \left (a^2-b^2\right )^3}-\frac {\log (\sin (x))}{a}\\ \end {align*}
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Mathematica [A]
time = 0.87, size = 172, normalized size = 0.97 \begin {gather*} \frac {\csc (x) (b+a \sin (x)) \left (-\frac {\left (8 a^2+21 a b+15 b^2\right ) \log (1-\sin (x))}{(a+b)^3}-\frac {\left (8 a^2-21 a b+15 b^2\right ) \log (1+\sin (x))}{(a-b)^3}+\frac {16 b^6 \log (b+a \sin (x))}{a (a-b)^3 (a+b)^3}+\frac {1}{(a+b) (-1+\sin (x))^2}+\frac {7 a+9 b}{(a+b)^2 (-1+\sin (x))}+\frac {1}{(a-b) (1+\sin (x))^2}+\frac {-7 a+9 b}{(a-b)^2 (1+\sin (x))}\right )}{16 (a+b \csc (x))} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.27, size = 160, normalized size = 0.90
method | result | size |
default | \(\frac {b^{6} \ln \left (b +a \sin \left (x \right )\right )}{\left (a +b \right )^{3} \left (a -b \right )^{3} a}+\frac {1}{2 \left (8 a +8 b \right ) \left (-1+\sin \left (x \right )\right )^{2}}-\frac {-7 a -9 b}{16 \left (a +b \right )^{2} \left (-1+\sin \left (x \right )\right )}+\frac {\left (-8 a^{2}-21 a b -15 b^{2}\right ) \ln \left (-1+\sin \left (x \right )\right )}{16 \left (a +b \right )^{3}}+\frac {1}{2 \left (8 a -8 b \right ) \left (\sin \left (x \right )+1\right )^{2}}-\frac {7 a -9 b}{16 \left (a -b \right )^{2} \left (\sin \left (x \right )+1\right )}+\frac {\left (-8 a^{2}+21 a b -15 b^{2}\right ) \ln \left (\sin \left (x \right )+1\right )}{16 \left (a -b \right )^{3}}\) | \(160\) |
risch | \(\frac {15 i x \,b^{2}}{8 \left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right )}+\frac {15 i x \,b^{2}}{8 \left (a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}\right )}+\frac {i x \,a^{2}}{a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}}+\frac {i \left (16 i a^{3} {\mathrm e}^{6 i x}-24 i a \,b^{2} {\mathrm e}^{6 i x}-5 a^{2} b \,{\mathrm e}^{7 i x}+9 b^{3} {\mathrm e}^{7 i x}+16 i a^{3} {\mathrm e}^{4 i x}-32 i a \,b^{2} {\mathrm e}^{4 i x}+3 a^{2} b \,{\mathrm e}^{5 i x}+b^{3} {\mathrm e}^{5 i x}+16 i a^{3} {\mathrm e}^{2 i x}-24 i a \,b^{2} {\mathrm e}^{2 i x}-3 a^{2} b \,{\mathrm e}^{3 i x}-b^{3} {\mathrm e}^{3 i x}+5 a^{2} b \,{\mathrm e}^{i x}-9 \,{\mathrm e}^{i x} b^{3}\right )}{4 \left (-a^{2}+b^{2}\right )^{2} \left ({\mathrm e}^{2 i x}+1\right )^{4}}+\frac {21 i x a b}{8 \left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right )}-\frac {i x}{a}-\frac {21 i x a b}{8 \left (a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}\right )}+\frac {i x \,a^{2}}{a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}}-\frac {2 i x \,b^{6}}{a \left (a^{6}-3 a^{4} b^{2}+3 a^{2} b^{4}-b^{6}\right )}-\frac {\ln \left ({\mathrm e}^{i x}-i\right ) a^{2}}{a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}}-\frac {21 \ln \left ({\mathrm e}^{i x}-i\right ) a b}{8 \left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right )}-\frac {15 \ln \left ({\mathrm e}^{i x}-i\right ) b^{2}}{8 \left (a^{3}+3 a^{2} b +3 a \,b^{2}+b^{3}\right )}-\frac {\ln \left (i+{\mathrm e}^{i x}\right ) a^{2}}{a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}}+\frac {21 \ln \left (i+{\mathrm e}^{i x}\right ) a b}{8 \left (a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}\right )}-\frac {15 \ln \left (i+{\mathrm e}^{i x}\right ) b^{2}}{8 \left (a^{3}-3 a^{2} b +3 a \,b^{2}-b^{3}\right )}+\frac {b^{6} \ln \left ({\mathrm e}^{2 i x}-1+\frac {2 i b \,{\mathrm e}^{i x}}{a}\right )}{a \left (a^{6}-3 a^{4} b^{2}+3 a^{2} b^{4}-b^{6}\right )}\) | \(662\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.27, size = 251, normalized size = 1.41 \begin {gather*} \frac {b^{6} \log \left (a \sin \left (x\right ) + b\right )}{a^{7} - 3 \, a^{5} b^{2} + 3 \, a^{3} b^{4} - a b^{6}} - \frac {{\left (8 \, a^{2} - 21 \, a b + 15 \, b^{2}\right )} \log \left (\sin \left (x\right ) + 1\right )}{16 \, {\left (a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}\right )}} - \frac {{\left (8 \, a^{2} + 21 \, a b + 15 \, b^{2}\right )} \log \left (\sin \left (x\right ) - 1\right )}{16 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )}} - \frac {{\left (5 \, a^{2} b - 9 \, b^{3}\right )} \sin \left (x\right )^{3} + 6 \, a^{3} - 10 \, a b^{2} - 4 \, {\left (2 \, a^{3} - 3 \, a b^{2}\right )} \sin \left (x\right )^{2} - {\left (3 \, a^{2} b - 7 \, b^{3}\right )} \sin \left (x\right )}{8 \, {\left ({\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \sin \left (x\right )^{4} + a^{4} - 2 \, a^{2} b^{2} + b^{4} - 2 \, {\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} \sin \left (x\right )^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 3.75, size = 260, normalized size = 1.46 \begin {gather*} \frac {16 \, b^{6} \cos \left (x\right )^{4} \log \left (a \sin \left (x\right ) + b\right ) + 4 \, a^{6} - 8 \, a^{4} b^{2} + 4 \, a^{2} b^{4} - {\left (8 \, a^{6} + 3 \, a^{5} b - 24 \, a^{4} b^{2} - 10 \, a^{3} b^{3} + 24 \, a^{2} b^{4} + 15 \, a b^{5}\right )} \cos \left (x\right )^{4} \log \left (\sin \left (x\right ) + 1\right ) - {\left (8 \, a^{6} - 3 \, a^{5} b - 24 \, a^{4} b^{2} + 10 \, a^{3} b^{3} + 24 \, a^{2} b^{4} - 15 \, a b^{5}\right )} \cos \left (x\right )^{4} \log \left (-\sin \left (x\right ) + 1\right ) - 8 \, {\left (2 \, a^{6} - 5 \, a^{4} b^{2} + 3 \, a^{2} b^{4}\right )} \cos \left (x\right )^{2} - 2 \, {\left (2 \, a^{5} b - 4 \, a^{3} b^{3} + 2 \, a b^{5} - {\left (5 \, a^{5} b - 14 \, a^{3} b^{3} + 9 \, a b^{5}\right )} \cos \left (x\right )^{2}\right )} \sin \left (x\right )}{16 \, {\left (a^{7} - 3 \, a^{5} b^{2} + 3 \, a^{3} b^{4} - a b^{6}\right )} \cos \left (x\right )^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\tan ^{5}{\left (x \right )}}{a + b \csc {\left (x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.40, size = 252, normalized size = 1.42 \begin {gather*} \frac {b^{6} \log \left ({\left | a \sin \left (x\right ) + b \right |}\right )}{a^{7} - 3 \, a^{5} b^{2} + 3 \, a^{3} b^{4} - a b^{6}} - \frac {{\left (8 \, a^{2} - 21 \, a b + 15 \, b^{2}\right )} \log \left (\sin \left (x\right ) + 1\right )}{16 \, {\left (a^{3} - 3 \, a^{2} b + 3 \, a b^{2} - b^{3}\right )}} - \frac {{\left (8 \, a^{2} + 21 \, a b + 15 \, b^{2}\right )} \log \left (-\sin \left (x\right ) + 1\right )}{16 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )}} - \frac {6 \, a^{5} - 16 \, a^{3} b^{2} + 10 \, a b^{4} + {\left (5 \, a^{4} b - 14 \, a^{2} b^{3} + 9 \, b^{5}\right )} \sin \left (x\right )^{3} - 4 \, {\left (2 \, a^{5} - 5 \, a^{3} b^{2} + 3 \, a b^{4}\right )} \sin \left (x\right )^{2} - {\left (3 \, a^{4} b - 10 \, a^{2} b^{3} + 7 \, b^{5}\right )} \sin \left (x\right )}{8 \, {\left (a + b\right )}^{3} {\left (a - b\right )}^{3} {\left (\sin \left (x\right ) + 1\right )}^{2} {\left (\sin \left (x\right ) - 1\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.30, size = 445, normalized size = 2.50 \begin {gather*} \frac {\frac {2\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2\,\left (2\,a\,b^2-a^3\right )}{a^4-2\,a^2\,b^2+b^4}-\frac {4\,{\mathrm {tan}\left (\frac {x}{2}\right )}^4\,\left (3\,a\,b^2-2\,a^3\right )}{a^4-2\,a^2\,b^2+b^4}+\frac {2\,{\mathrm {tan}\left (\frac {x}{2}\right )}^6\,\left (2\,a\,b^2-a^3\right )}{a^4-2\,a^2\,b^2+b^4}+\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^7\,\left (3\,a^2\,b-7\,b^3\right )}{4\,\left (a^4-2\,a^2\,b^2+b^4\right )}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^3\,\left (11\,a^2\,b-15\,b^3\right )}{4\,\left (a^4-2\,a^2\,b^2+b^4\right )}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^5\,\left (11\,a^2\,b-15\,b^3\right )}{4\,\left (a^4-2\,a^2\,b^2+b^4\right )}+\frac {b\,\mathrm {tan}\left (\frac {x}{2}\right )\,\left (3\,a^2-7\,b^2\right )}{4\,\left (a^4-2\,a^2\,b^2+b^4\right )}}{{\mathrm {tan}\left (\frac {x}{2}\right )}^8-4\,{\mathrm {tan}\left (\frac {x}{2}\right )}^6+6\,{\mathrm {tan}\left (\frac {x}{2}\right )}^4-4\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2+1}-\ln \left (\mathrm {tan}\left (\frac {x}{2}\right )-1\right )\,\left (\frac {5\,b}{8\,{\left (a+b\right )}^2}+\frac {1}{a+b}+\frac {b^2}{4\,{\left (a+b\right )}^3}\right )-\ln \left (\mathrm {tan}\left (\frac {x}{2}\right )+1\right )\,\left (\frac {b^2}{4\,{\left (a-b\right )}^3}-\frac {5\,b}{8\,{\left (a-b\right )}^2}+\frac {1}{a-b}\right )+\frac {\ln \left ({\mathrm {tan}\left (\frac {x}{2}\right )}^2+1\right )}{a}-\frac {b^6\,\ln \left (b\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2+2\,a\,\mathrm {tan}\left (\frac {x}{2}\right )+b\right )}{-a^7+3\,a^5\,b^2-3\,a^3\,b^4+a\,b^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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